Find graphically the resultant of the system of forces indicated in the figure. To do that, we will first redraw the vectors to scale. And to set the scale, we use the vector of greatest magnitude, which is 220 N, and we choose that 220 N is equal to 11 cm. Now we are going to convert each of the magnitudes of the remaining vectors to centimeters and we start with 180 N. and we write 180 new 1 and multiply it by our conversion factor in fraction form. That is, in the numerator we write 11 cm and in the denominator 220 N. And we observe that in the numerator of our first fraction and in the denominator of our second fraction we have units of newtons, therefore these cancel out. And when performing the operations we have that 180 * 11 cm is = 1980 cm divided by 1 * 220 is equal to 220 and this division is equal to 9 cm. So new is equivalent to 9 cm. And similarly for the other magnitudes of the vectors we have that 140 N is equivalent to 7 cm. and 80 N is equivalent to 4 cm. And we redraw each of these vectors to the chosen scale and begin by drawing the vector of magnitude 220 N. For this, we first measure the angle of inclination, which is 60º, and we do it with the protractor. And here it is. We already observed that 60º is located here. Now with our ruler we measure 11 cm and draw the vector. And here it is. We continue. And at the end of this vector we will draw the vector of magnitude 180 N. For that, we will first measure the angle of inclination with the protractor. First we observe that this angle of 30º below the horizontal is equivalent to this angle of 330º above the horizontal. And here it is . And we observe that this 330º angle is located here. And now we measure 9 cm and draw the vector. And here it is. We continue. And at the end of this vector we are going to draw the vector of magnitude 140 N. For that we measure 7 cm with the ruler and draw the vector. And here it is. Next, at the end of this vector, we will draw the vector of magnitude 80 N. To do this, we first measure its angle of inclination, which is 25º, below the horizontal in the third quadrant, but this angle is equivalent to 205º. And we measured it with the protractor. We already observed that this angle is located here and we measured 4 cm and drew the vector. And here it is. And finally, we draw the resultant force vector that goes from the origin to the end of the last vector. And here it is. And we measured its magnitude with the ruler. We already observed that it measures 10.3 cm. And now we are going to convert 10.3 cm to newtons. To do this, we write 10.3 cm / 1 and multiply it by our conversion factor in fraction form. That is, in the numerator we write 220 N and in the denominator 11 cm. And the centimeter units in the numerator cancel out with the centimeter units in the denominator. And by performing these operations, the result is equal to 206 N. Therefore, 10.3 cm is equivalent to 206 N. And next we are going to measure its angle of inclination with the protractor. And here it is. And we observe that it measures 340º or below the horizontal 20º. Therefore, to conclude, the resultant force vector has a magnitude of 206 N and a direction of 340º. Well, friends, thanks for visiting. If you liked this video, subscribe and share it. More on this topic at vual.